📖 Gioi Thieu Cau Thu
P. Olkowski (ten day du: Paweł Mirosław Olkowski) la cau thu bong da chuyen nghiep mang quoc tich Poland , hien dang thi dau o vi tri Hậu vệ cho cau lac bo Gornik Zabrze.
Sinh ngay 13/02/1990 tai Ozimek, Poland (hien 35 tuoi). Voi chieu cao 184 va can nang 76 , anh co the hinh ly tuong cho vi tri Hậu vệ.
Trong mua giai 2025 tai Cup, P. Olkowski da ra san 2 tran (0 tran da chinh), ghi duoc 0 ban thang va co 0 pha kien tao. Ve ky luat, anh nhan 1 the vang va 0 the do.
👤 Thong Tin Ca Nhan
Ho ten day du
Paweł Mirosław Olkowski
Ten thuong goi
P. Olkowski
Quoc tich
Poland
Ngay sinh
13/02/1990
Noi sinh
Ozimek, Poland
Tuoi
35
Chieu cao
184
Can nang
76
Vi tri
Hậu vệ
📊 Thong Ke Mua 2025
Giai dau
Cup
So tran ra san
2
So tran da chinh
0
Phut thi dau
0'
Ban thang
0
Kien tao
0
So lan sut
0
Sut trung dich
0
Chuyen thanh cong
0%
The vang
1
The do
0
🏆 Thong Ke Cac Giai Khac
| Giai dau | Doi bong | Tran | Ban | KT | Vang | Do |
|---|---|---|---|---|---|---|
| Ekstraklasa |
Gornik Zabrze
|
25 | 0 | 1 | 0 | 0 |
